Geometric Sequence
The calculator finds the n-th term, the common ratio, the sum of the first n terms of a geometric sequence and the sum of an infinite geometric series. Exact answer and step-by-step solution.
The geometric sequence calculator finds the n-th term, the common ratio and the sum of the first n terms, as well as the sum of an infinite geometric series. A sequence can be given by its first term and common ratio, by the first and the n-th term, or by any two terms. When two ratios fit (q and −q), the calculator solves both cases. The answer is exact — in fractions, with a step-by-step solution and a table of the first terms.
What is a geometric sequence
A geometric sequence (geometric progression) is a sequence of non-zero numbers in which each term after the first is obtained by multiplying the previous term by the same number q. This number is called the common ratio.
bn+1 = bn · q, b1 ≠ 0, q ≠ 0
For example, 3, 6, 12, 24, 48, … is a geometric sequence with b1 = 3 and q = 2. When q < 0, the signs of the terms alternate: 1, −2, 4, −8, …
Main formulas
| What to find | Formula |
|---|---|
| n-th term | bn = b1 · qn−1 |
| Common ratio | q = bn+1 / bn |
| Sum of the first n terms (q ≠ 1) | Sn = b1(qn − 1) / (q − 1) |
| Sum when q = 1 | Sn = n · b1 |
| Infinite series (|q| < 1) | S = b1 / (1 − q) |
| Mean property | bn2 = bn−1 · bn+1 |
The absolute value of every term except the first is the geometric mean of its neighbors — this is where the name comes from.
Example 1. b1 = 3, q = 2. Find b10 and S10.
b10 = 3 · 29 = 1536
S10 = 3 · (210 − 1) / (2 − 1) = 3069
How to find the ratio from two terms
The ratio of two terms equals q to the power of the difference of their positions: bm / bk = qm−k. Then take the root of degree m − k. If that degree is even and the ratio is positive, two common ratios fit: q and −q.
Example 2. b1 = 2, b5 = 162.
q4 = 162 / 2 = 81 ⇒ q = 3 or q = −3.
For q = 3: S5 = 242, for q = −3: S5 = 122.
Infinite geometric series
If |q| < 1, the terms approach zero and the partial sums Sn approach a finite number S = b1 / (1 − q). If |q| ≥ 1, the series has no finite sum.
Example 3. 8 + 4 + 2 + 1 + … : b1 = 8, q = 1/2.
S = 8 / (1 − 1/2) = 16
This formula turns a repeating decimal into a fraction: 0.(3) = 0.3 + 0.03 + … = 0.3 / (1 − 0.1) = 1/3.
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